Which of the following nuclear fragments corresponding to nuclear fission between neutron $\left({ }_{0}^{1} \mathrm{n}\right)$ and uranium isotope $\left({ }_{92}^{235} \mathrm{U}\right)$ is correct:

(D) ${ }_{56}^{144} \mathrm{Ba}+{ }_{36}^{89} \mathrm{Kr}+3_{0}^{1} \mathrm{n}$

(A) ${ }_{56}^{144} \mathrm{Ba}+{ }_{36}^{89} \mathrm{Kr}+4{ }_{0}^{1} \mathrm{n}$

(B) ${ }_{56}^{140} \mathrm{Xe}+{ }_{38}^{94} \mathrm{Sr}+3_{0}^{1} \mathrm{n}$

(C) ${ }_{51}^{153} \mathrm{Sb}+{ }_{41}^{99} \mathrm{Nb}+3_{0}^{1} \mathrm{n}$

JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Modern Physics

Which of the following nuclear fragments corresponding to nuclear fission between neutron

(_{0}^{1} n)

and uranium isotope

(_{92}^{235} U)

is correct:

(A) $_{56}^{144} Ba +_{36}^{89} Kr + 4_{0}^{1} n$
(B) $_{56}^{140} Xe +_{38}^{94} Sr + 3_{0}^{1} n$
(C) $_{51}^{153} Sb +_{41}^{99} Nb + 3_{0}^{1} n$
(D) $_{56}^{144} Ba +_{36}^{89} Kr + 3_{0}^{1} n$ ✓ Correct

Answer: (D)

Solution

Balance mass number and atomic number for

_{92}^{235} U +_{0}^{1} n ⟶ A + B + x_{0}^{1} n .

Option D:

_{56}^{144} Ba +_{36}^{89} Kr + 3_{0}^{1} n

.
Mass:

144 + 89 + 3 = 236 = 235 + 1

✓. Charge:

56 + 36 = 92

✓.
(The other options fail one of these balances.) Option D.

JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Single correct option

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