Which figure shows the correct variation of applied potential difference (V) with photoelectric current (I) at two different intensities of light ( I1<I2 ) of same wavelengths :
(A)(see structure)
(B)(see structure)
(C)(see structure)✓ Correct
(D)(see structure)
Answer: (C)
Solution
Stopping potential depends only on frequency (wavelength), not intensity. Both beams have the same wavelength ⇒ same stopping potential −V0 (same x-intercept).
Saturation current is proportional to intensity, so with I2>I1 the I2 curve saturates at a higher current. The correct graph has a common −V0 and the I2 plateau above the I1 plateau ⇒ option C.
JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Single correct option