JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Wave Optics

In Young's double slit experiment, carried out with light of wavelength

5000 \overset{˚}{A}

, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at

x = 0 cm

. The value of x for third maxima is ______ mm.

Answer: 10

Solution

Fringe position of the

n

-th maximum:

y_{n} = \frac{nλ D}{d}

. For

n = 3

y_{3} = \frac{3 ( 5000 \times 1 0 ^{- 10} ) ( 2 )}{0.3 \times 1 0 ^{- 3}} = \frac{3 \times 5 \times 1 0 ^{- 7} \times 2}{3 \times 1 0 ^{- 4}} = 10 \times 1 0^{- 3} m = 10 mm .

JEE Main · 2024 · 05 Apr 2024 · Shift 1 · Integer answer

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