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JEE Main · 2024 · 06 Apr 2024 · Shift 1 · Chapter_pending

Match List I with List II

Answer: A → IV, B → III, C → II, D → I

Solution

Torque

τ = r \times F

has the dimensions of energy:

[M^{1} L^{2} T^{- 2}]

\to

(IV).
Magnetic field

B = \frac{F}{q v}

:

[M^{1} T^{- 2} A^{- 1}]

\to

(III).
Magnetic moment

M = I A

:

[L^{2} A^{1}]

\to

(II).
Permeability

μ_{0}

(from

B = \frac{μ _{0} I d l}{4 π r ^{2}}

):

[M^{1} L^{1} T^{- 2} A^{- 2}]

\to

(I).
So A-IV, B-III, C-II, D-I.

JEE Main · 2024 · 06 Apr 2024 · Shift 1 · Match the columns

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