The 'spin only' magnetic moment value of $\mathrm{MO}_{4}{ }^{2-}$ is ______ BM. (Where M is a metal having least metallic radii. among $\mathrm{Sc}, \mathrm{Ti}, \mathrm{V}, \mathrm{Cr}, \mathrm{Mn}$ and Zn ). (Given atomic number : $\mathrm{Sc}=21, \mathrm{Ti}=22, \mathrm{~V}=23$, $\mathrm{Cr}=24, \mathrm{Mn}=25$ and $\mathrm{Zn}=30$ )

JEE Main · 2024 · 08 Apr 2024 · Shift 1 · d and f Block Elements

The 'spin only' magnetic moment value of

MO_{4}^{2 -}

is
______ BM. (Where M is a metal having least metallic radii. among

Sc, Ti, V, Cr, Mn

and Zn ).
(Given atomic number :

Sc = 21, Ti = 22, V = 23

Cr = 24, Mn = 25

and

Zn = 30

)

Answer: 0

Least metallic radius among Sc, Ti, V, Cr, Mn, Zn is

C r

. In

C r O_{4}^{2 -}

chromium is

+ 6

(

d^{0}

), so there are no unpaired electrons and the spin-only moment is

0

BM.

JEE Main · 2024 · 08 Apr 2024 · Shift 1 · Integer answer