A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The glow of the bulb:
(A)increases✓ Correct
(B)remains same
(C)becomes zero
(D)decreases
Answer: (A)
Solution
Adding a dielectric raises C, so XC=ωC1 falls, impedance Z=R2+XC2 falls, current rises — the bulb glows brighter (increases). Option (1).
JEE Main · 2024 · 09 Apr 2024 · Shift 1 · Single correct option