Given below are two statements:
Statement (I): The group in Aniline is ortho and para directing and a powerful activating group.
Statement (II): Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).
In the light of the above statements, choose the most appropriate answer from the options given below :
Statement (I): The group in Aniline is ortho and para directing and a powerful activating group.
Statement (II): Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).
In the light of the above statements, choose the most appropriate answer from the options given below :
- (A)Both Statement I and Statement II are correct✓ Correct
- (B)Both Statement I and Statement II are incorrect
- (C)Statement I is incorrect but Statement II is correct
- (D)Statement I is correct but Statement II is incorrect
Answer: (A)
Solution
The group in aniline is a powerful electron donor through resonance (+M effect), so it strongly activates the benzene ring and directs incoming electrophiles to the ortho and para positions — Statement I is correct. In Friedel-Crafts reactions, the Lewis acid catalyst (AlCl) forms a complex with the lone pair on nitrogen; this makes the ring strongly deactivated (essentially converting into an electron-withdrawing group), so aniline does not undergo Friedel-Crafts alkylation/acylation — Statement II is correct. Both statements are correct.
JEE Main · 2024 · 01 Feb 2024 · Shift 1 · Single correct option