JEE Main · 2024 · 31 Jan 2024 · Shift 1 · Haloalkanes and Haloarenes

The product ( C ) in the below mentioned reaction is:

(A)Propan-1-ol
(B)Propene
(C)Propyne
(D)Propan-2-ol✓ Correct

Answer: (D)

Solution

C H_{3} C H_{2} C H_{2} Br K O H a l c . C H_{3} CH = C H_{2} (A) H B r C H_{3} CHBrC H_{3} (B) K O H a q . C H_{3} CH (OH) C H_{3} (C)

Alcoholic KOH eliminates HBr from 1-bromopropane to give propene (A). Markovnikov addition of HBr to propene gives 2-bromopropane (B). Aqueous KOH then substitutes the bromide to give propan-2-ol (C).

JEE Main · 2024 · 31 Jan 2024 · Shift 1 · Single correct option

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