A light string passing over a smooth light fixed pulley connects two blocks of masses m1 and m2. If the acceleration of the system is g/8, then the ratio of masses is
(A)79✓ Correct
(B)18
(C)34
(D)35
Answer: (A)
Solution
For an Atwood machine, the acceleration of the system is
a=m1+m2(m1−m2)g
Setting a=g/8:
m1+m2m1−m2=81
8m1−8m2=m1+m2
7m1=9m2
m2m1=79
JEE Main · 2024 · 31 Jan 2024 · Shift 2 · Single correct option