If the area of the region bounded by the curves y=4−4x2 and y=2x−4 is equal to α, then 6α equals
(A)250✓ Correct
(B)210
(C)240
(D)220
Answer: (A)
Solution
The curves meet where 4−4x2=2x−4, which reduces to x2+2x−24=0, giving x=−6 and x=4. Between these abscissae the parabola lies above the line, so α=∫−64[(4−4x2)−2x−4]dx=∫−64(6−4x2−2x)dx. The antiderivative 6x−12x3−4x2 evaluated from −6 to 4 gives 344−(−27)=3125. Therefore 6α=6⋅3125=250.
JEE Main · 2025 · 07 Apr 2025 · Shift 1 · Single correct option