JEE Main · 2025 · 03 Apr 2025 · Shift 2 · Hydrocarbons

In the following series of reactions identify the major products A & B respectively.

Bromobenzene

(A)(see structure)
A
(B)(see structure)
A
B
✓ Correct
(C)(see structure)
A
B
(D)(see structure)
A
B

Answer: (B)

Solution

Bromobenzene is sulfonated by

S O_{3} / H_{2} S O_{4}

; bromine is an ortho/para director and the bulky

- S O_{3} H

enters mainly at the para position, so product A is

p

-bromobenzenesulfonic acid. In the next step

B r_{2} /Fe

introduces a second bromine: the ring now bears

- Br

(ortho/para directing) and

- S O_{3} H

(meta directing), and both effects point to the carbon that is ortho to the existing bromine and meta to the sulfonic acid group. The incoming bromine settles there, so product B is

3, 4

-dibromobenzenesulfonic acid.

JEE Main · 2025 · 03 Apr 2025 · Shift 2 · Single correct option

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