Which of the following represents the correct trend for the mentioned property?
A. - First Ionization Energy
B. - Electron Affinity
C. - Metallic character
D. - Basic character
Choose the correct answer from the option given below.
A. - First Ionization Energy
B. - Electron Affinity
C. - Metallic character
D. - Basic character
Choose the correct answer from the option given below.
- (A)A, B and D only✓ Correct
- (B)A, B, C and D
- (C)A and B only
- (D)B and C only
Answer: (A)
Solution
First ionization energy rises across a period and falls down a group, and the half-filled 3p of phosphorus raises it above sulphur, giving F P S B, so trend A is correct. Electron affinity is greatest for group 17, and within it chlorine exceeds fluorine because of the small, electron-crowded 2p shell of F, giving Cl F S P, so trend B is correct. Metallic character should read K Mg Al B, so the quoted K Al Mg B is wrong and trend C fails. Basic character of the oxides falls across a period and rises down a group, giving KO NaO MgO AlO, so trend D is correct. The correct trends are A, B and D only.
JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Single correct option