JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Some Basic Concepts of Chemistry

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14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K.
Which of the following statements is incorrect?
[Given: Molar mass in

g mol^{- 1}

Ca - 40, Cl - 35.5, H - 1

]

(A) $0.35 mol$ of $H_{2}$ gas is evolved.
(B) $7.84 L$ of $H_{2}$ gas is evolved.
(C)33.3 g of $CaCl_{2}$ is produced.✓ Correct
(D)The limiting reagent is calcium metal.

Answer: (C)

Solution

The amount of calcium is

14.0/40 = 0.35 mol

, and with HCl in excess calcium is the limiting reagent in Ca

+

2HCl

\to

CaCl

_{2}

+

_{2}

. Each mole of calcium releases one mole of hydrogen, so

0.35 mol

of H

_{2}

forms, occupying

0.35 \times 22.4 = 7.84 L

at 273 K and 1 atm. The mass of CaCl

_{2}

produced is

0.35 \times 111 = 38.85 g

, not 33.3 g. The incorrect statement is that 33.3 g of CaCl

_{2}

is produced.

JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Single correct option

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JEE Main · 2026 · 21 Jan 2026 · Shift 1 · Some Basic Concepts of Chemistry

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