The reaction shows a cyclic alkene undergoing hydrobromination with HBr in the presence of peroxide. In the presence of peroxide, the reaction follows an anti-Markovnikov pathway (free radical mechanism), where Br adds to the less substituted carbon.
The starting material is 1-methylcyclopentene. Under anti-Markovnikov addition, the Br will add to the terminal carbon of the double bond, and H will add to the more substituted carbon, giving 1-bromo-1-methylcyclopentane.
The correct product is shown in option (2).
JEE Main · 2026 · 23 Jan 2026 · Shift 2 · Single correct option