The number of points, where the curve y=x5−20x3+50x+2 crosses the x-axis, is ____.
Answer: 5
Solution
Differentiating, y′=5x4−60x2+50=5(x4−12x2+10), which vanishes at x2=6±26, giving four turning points at x≈−3.3,−0.95,0.95,3.3. Evaluating the polynomial at these points gives approximately +164 at x≈−3.3, −29 at x≈−0.95, +33 at x≈0.95 and −160 at x≈3.3. Since the curve tends to −∞ as x→−∞ and to +∞ as x→+∞, it rises to a positive maximum, falls to a negative minimum, rises to a positive maximum, falls to a negative minimum, and finally increases without bound. The value changes sign across each of the five monotone stretches, so the curve meets the axis once in each. The curve crosses the x-axis at 5 points.