JEE Main · 2023 · 11 Apr 2023 · Shift 2 · Atomic Structure

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The number of correct statements from the following ______
A. For 1s orbital, the probability density is maximum at the nucleus.
B. For 2 s orbital, the probability density first increases to maximum and then decreases sharply to zero.
C. Boundary surface diagrams of the orbitals encloses a region of 100% probability of finding the electron.
D. p and d-orbitals have 1 and 2 angular nodes respectively.
E. Probability density of p-orbital is zero at the nucleus.

Answer: 3

Solution

Statement A: Correct. For 1s orbital, probability density (ψ²) is maximum at the nucleus.

Statement B: Incorrect. For 2s orbital, probability density first decreases from the nucleus, then increases to a maximum, then decreases again.

Statement C: Incorrect. Boundary surface diagrams typically enclose a region of ~90-95% probability, not 100%.

Statement D: Correct. p-orbitals have 1 angular node, d-orbitals have 2 angular nodes.

Statement E: Correct. p-orbitals have a node at the nucleus, so probability density is zero there.

Correct statements: A, D, E = 3.

JEE Main · 2023 · 11 Apr 2023 · Shift 2 · Integer answer

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