In the given reaction cycle $\mathrm{CaCl}_{2}+\mathrm{Na}_{2} \mathrm{CO}_{3} \longrightarrow \underline{\mathrm{X}}+\underline{\mathrm{Y}}$ $\mathrm{X}, \mathrm{Y}$ and Z respectively are

(C) X: $\mathrm{CaCO}_{3}$, Y: NaCl, Z: HCl

(B) X: $\mathrm{CaCO}_{3}$, Y: NaCl, Z: KCl

(D) X: CaO, Y: $\mathrm{NaCl}+\mathrm{CO}_{2}$, Z: NaCl

JEE Main · 2023 · 12 Apr 2023 · Shift 1 · s-Block Elements

In the given reaction cycle

CaCl_{2} + Na_{2} CO_{3} ⟶ \underline{X} + \underline{Y}

X, Y

and Z respectively are

Answer: (C)

Mixing calcium chloride with sodium carbonate precipitates calcium carbonate and leaves sodium chloride in solution,

CaCl X_{2} + Na X_{2} CO X_{3} CaCO X_{3} + 2 NaCl

, so X is

CaCO X_{3}

and Y is

NaCl

. To close the cycle the calcium carbonate is treated with hydrochloric acid, which regenerates calcium chloride,

CaCO X_{3} + 2 HCl CaCl X_{2} + H X_{2} O + CO X_{2}

. Hence X is calcium carbonate, Y is sodium chloride and Z is hydrochloric acid.

JEE Main · 2023 · 12 Apr 2023 · Shift 1 · Single correct option