Write the truth table for the combination of gates shown in the figure.
Answer: The combination acts as a NAND gate: 00→1,10→1,01→1,11→0.
Solution
The network is an AND gate followed by a NOT gate, so the output is Y=A⋅B. Output is 0 only when both inputs are 1; otherwise it is 1: 00→1,10→1,01→1,11→0. Y=A⋅B(NAND)