Explain the function of the base region of a transistor. Why is this region made thin and lightly doped? Draw a circuit diagram to study the input and output characteristics of an n-p-n transistor in common emitter (CE) configuration. Show these characteristics graphically. Explain how the current amplification factor of the transistor is calculated using the output characteristics.
Solution
The base controls the number of majority carriers passing from the emitter to the collector, which makes transistor action possible.
It is made thin and lightly doped so that very few of the injected carriers recombine in the base, allowing most (~95-98%) to reach the collector and give a large collector current.
Circuit: connect the n-p-n transistor in CE configuration with (through a resistor) biasing the base and biasing the collector through , with meters for , , , .
Input characteristic: versus at fixed . Output characteristic: versus for several fixed .
From the output characteristics, at a fixed ,
It is made thin and lightly doped so that very few of the injected carriers recombine in the base, allowing most (~95-98%) to reach the collector and give a large collector current.
Circuit: connect the n-p-n transistor in CE configuration with (through a resistor) biasing the base and biasing the collector through , with meters for , , , .
Input characteristic: versus at fixed . Output characteristic: versus for several fixed .
From the output characteristics, at a fixed ,
CBSE Class 12 Board · 2006 · All India · Subjective