Find the value of a if [a−b2a−b2a+c3c+d]=[−10513].Answer: a=1SolutionEquate corresponding entries: a−b=−1 and 2a−b=0. Subtracting the first from the second eliminates b:(2a−b)−(a−b)=0−(−1) ⇒ a=1.a=1CBSE Class 12 Board · 2013 · Subjective