If A=2−13023035, then find A(adjA).Answer: A(adjA)=2I=200020002SolutionUse the standard identity A(adjA)=∣A∣I. Expand ∣A∣ along the first row:∣A∣=2(2⋅5−3⋅3)=2(10−9)=2.ThereforeA(adjA)=2I=200020002.CBSE Class 12 Board · 2020 · Subjective