Using matrices, solve the following system of equations:x+2y+z=1,2x−y+z=5,3x+y−z=0.Answer: x=1, y=−1, z=2SolutionForm AX=B with A=1232−1111−1, B=150; ∣A∣=0 so X=A−1B.Solving gives x=1, y=−1, z=2 (check: 1−2+2=1, 2+1+2=5, 3−1−2=0).x=1, y=−1, z=2CBSE Class 12 Board · 2006 · Subjective