Using matrices, solve the following system of equations:x+2y+z=7,x+3z=11,2x−3y=1.Answer: x=2, y=1, z=3SolutionForm AX=B with A=11220−3130, B=7111; ∣A∣=0, so X=A−1B.Solving gives x=2, y=1, z=3 (check: 2+2+3=7, 2+9=11, 4−3=1).x=2, y=1, z=3CBSE Class 12 Board · 2011 · Subjective