Using matrices, solve the following system of equations:x+2y−3z=−4,2x+3y+2z=2,3x−3y−4z=11.Answer: x=3, y=−2, z=1SolutionForm AX=B with A=12323−3−32−4, B=−4211. Here ∣A∣=67=0 and A−1=671−614−15175913−8−1, soX=A−1B=671201−13467=3−21.x=3, y=−2, z=1CBSE Class 12 Board · 2011 · Subjective