Using matrices, solve the following system of linear equations:x−y+2z=7,3x+4y−5z=−5,2x−y+3z=12.Answer: x=2, y=1, z=3SolutionForm AX=B with A=132−14−12−53, B=7−512. Here ∣A∣=4=0, and solving X=A−1B givesx=2, y=1, z=3.(Check: 2−1+6=7, 6+4−15=−5, 4−1+9=12.)x=2, y=1, z=3CBSE Class 12 Board · 2012 · Subjective