If A=231−3215−4−2, find A−1. Use it to solve the system of equations2x−3y+5z=11,3x+2y−4z=−5,x+y−2z=−3.Answer: x=1, y=2, z=3; A−1=0−2−1195−2−23−13SolutionHere ∣A∣=−1. From the cofactors, adjA=021−1−9−522313, soA−1=∣A∣1adjA=0−2−1195−2−23−13.With B=11−5−3,X=A−1B=123.x=1, y=2, z=3CBSE Class 12 Board · 2018 · Subjective