Using the valence bond theory, predict the geometry and magnetic behaviour of [CoF]. (Atomic number of Co = 27)
Answer: Octahedral, sp³d² (outer orbital); paramagnetic — 4 unpaired electrons.
Solution
Co = 3d. F is a weak-field ligand — no pairing: te retains 4 unpaired electrons.
The ligands use 4s, three 4p and two 4d orbitals: spd — an outer-orbital (high-spin) complex.
Geometry: octahedral.
Magnetism: 4 unpaired electrons → paramagnetic, μ = √24 ≈ 4.90 BM.
The ligands use 4s, three 4p and two 4d orbitals: spd — an outer-orbital (high-spin) complex.
Geometry: octahedral.
Magnetism: 4 unpaired electrons → paramagnetic, μ = √24 ≈ 4.90 BM.
CBSE Class 12 Board · 2010 · Delhi Compartment · Subjective