CBSE Class 12 · 2008 · All India · Coordination CompoundsShort Answer

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a) What is the basis of the formation of the spectrochemical series?
b) Draw the structures of the geometrical isomers of the following coordination complexes:
[Co(NH

_{3}

)

_{3}

_{3}

] and [CoCl

_{2}

(en)

_{2}

]

^{+}

Solution

(a) The spectrochemical series arranges ligands in order of increasing crystal-field splitting energy Δ that they cause; the order is established experimentally from the absorption spectra of complexes:

I^{-} < B r^{-} < C l^{-} < F^{-} < O H^{-} < H_{2} O < N H_{3} < en < C N^{-} < CO

(b) [Co(NH

_{3}

)

_{3}

_{3}

] (MA

_{3}

_{3}

): \textit{facial (fac)} — three Cl on one triangular face; \textit{meridional (mer)} — three Cl spanning a meridian (two trans, one cis).
[CoCl

_{2}

(en)

_{2}

]

^{+}

(M(AA)

_{2}

_{2}

): \textit{cis} — Cl's adjacent (chiral form); \textit{trans} — Cl's opposite.

CBSE Class 12 Board · 2008 · All India · Subjective

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CBSE Class 12 · 2008 · All India · Coordination CompoundsShort Answer

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