CBSE Class 12 · 2016 · All India · Coordination CompoundsShort Answer

i) For the complex [Fe(CN)

_{6}

]

^{4 -}

, write the hybridisation, magnetic character and spin type of the complex. (Atomic number: Fe = 26)
ii) Draw one of the geometrical isomers of the complex [Co(en)

_{2}

_{2}

]

^{+}

which is optically active.

Solution

(i) Fe

^{2 +}

= 3d

^{6}

; CN

^{-}

(strong field) pairs all six electrons: hybridisation \textbf{d

^{2}

^{3}

}, \textbf{diamagnetic}, \textbf{low-spin} (inner-orbital) complex.
(ii) The \textbf{cis-isomer} of [Co(en)

_{2}

_{2}

]

^{+}

— two Cl

^{-}

on adjacent vertices with the en rings spanning the rest — has no plane of symmetry and exists as d/l enantiomers; draw the octahedron with adjacent Cl's (the trans form is inactive).

CBSE Class 12 Board · 2016 · All India · Subjective

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