The total number of stereoisomers for the complex $\left[\mathrm{Cr}(\mathrm{ox})_{2} \mathrm{ClBr}\right]^{3-}$ (where ox $=$ oxalate) is:

JEE Main · 2023 · 13 Apr 2023 · Shift 2 · Coordination Compounds

The total number of stereoisomers for the complex

[Cr (ox)_{2} ClBr]^{3 -}

(where ox

=

oxalate) is:

(A)2
(B)3✓ Correct
(C)1
(D)4

Answer: (B)

Solution

The ion

[Cr (ox) X_{2} ClBr] X^{3 -}

is octahedral, with the two symmetric bidentate oxalate ligands filling four coordination sites and chloride and bromide occupying the other two. When Cl and Br lie opposite one another the complex has a plane of symmetry and is optically inactive, giving a single trans form. When Cl and Br are adjacent the complex has no plane of symmetry and is chiral, existing as a non-superimposable pair of d and l enantiomers. Adding the lone trans form to the two cis optical isomers gives a total of three stereoisomers.

JEE Main · 2023 · 13 Apr 2023 · Shift 2 · Single correct option

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