JEE Main · 2023 · 24 Jan 2023 · Shift 1 · Kinematics

A stream of a positively charged particles having

\frac{q}{m} = 2 \times 1 0^{11} \frac{C}{k g}

and velocity

v_{0} = 3 \times 1 0^{7} \hat{i}

m/s is deflected by an electric field

1.8 \hat{j}

kV/m. The electric field exists in a region of 10 cm along x direction. Due to the electric field, the deflection of the charge particles in the y direction is ______ mm.

Answer: 2

Solution

The transverse field gives the particle an acceleration

a = \frac{q E}{m} = (2 \times 1 0^{11}) (1.8 \times 1 0^{3}) = 3.6 \times 1 0^{14} m/s^{2}

. Travelling at

3 \times 1 0^{7} m/s

, it spends

t = \frac{0.10}{3 \times 1 0 ^{7}} = \frac{1}{3} \times 1 0^{- 7} s

inside the

10 cm

region. The sideways shift over this time is

y = \frac{1}{2} a t^{2} = \frac{1}{2} (3.6 \times 1 0^{14}) (\frac{1}{3} \times 1 0^{- 7})^{2} = 2 \times 1 0^{- 3} m

, that is

2 mm

JEE Main · 2023 · 24 Jan 2023 · Shift 1 · Integer answer

Practise more: all JEE Main PYQs on Kinematics →

JEE Main · 2023 · 24 Jan 2023 · Shift 1 · Kinematics

Solution

More JEE Main questions on Kinematics