Let P(a1,b1) and Q(a2,b2) be two distinct points on a circle with center C(2,3). Let O be the origin and OC be perpendicular to both CP and CQ . If the area of the triangle OCP is 235, then a12+a22+b12+b22 is equal to ____ .
Answer: 24
Solution
With C=(2,3), OC=2+3=5, and OC⊥CP makes triangle OCP right-angled at C. Its area 21⋅OC⋅CP=235 gives CP=7, which is the circle's radius, so CQ=7 too. By the right angles at C, OP2=OC2+CP2=5+7=12 and OQ2=OC2+CQ2=12. Hence a12+b12+a22+b22=OP2+OQ2=24.
JEE Main · 2023 · 30 Jan 2023 · Shift 2 · Integer answer