A uniform electric field of 10 N/C is created between two parallel charged plates (as shown in figure). An electron enters the field symmetrically between the plates with a kinetic energy 0.5 eV. The length of each plate is 10 cm. The angle (θ) of deviation of the path of electron as it comes out of the field is ______ (in degree).
Answer: 45
Solution
The electron enters along the plates with horizontal kinetic energy 21mvx2=0.5e, so vx2=me. While crossing the length L it gains a transverse velocity vy=meE⋅vxL. The deflection obeys tanθ=vxvy=mvx2eEL=eeEL=EL=10×0.1=1. The path leaves the field turned through θ=45∘.
JEE Main · 2023 · 25 Jan 2023 · Shift 1 · Integer answer