JEE Main · 2023 · 01 Feb 2023 · Shift 2 · Surface Chemistry

The Freundlich isotherm $\frac{x}{m}=K{P}^{1/n}$ becomes, on taking logarithms, $\log \frac{x}{m}=\log K+\frac{1}{n}\log P$. Plotting $\log \frac{x}{m}$ against $\log P$ gives a straight line whose slope is $\frac{1}{n}$ and whose intercept on the vertical axis is $\log K$. Comparing with the given line $y=3x+2.505$, the slope gives $\frac{1}{n}=3$ and the intercept gives $\log K=2.505$.