JEE Main · 2022 · 27 Jul 2022 · Shift 1 · Kinematics

A bullet is shot vertically downwards with an initial velocity of

100 m / s

from a certain height. Within 10 s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time

t = 20 s

will be :

(

Take

g = 10 m / s^{2})

(A)(see graph)
✓ Correct
(B)(see graph)
(C)(see graph)
(D)(see graph)

Answer: (A)

Solution

Taking downward as negative, the velocity equation is

v = - 100 - 10 t

. At

t = 0

v = - 100

m/s. At

t = 10

v = - 100 - 100 = - 200

m/s. The bullet then comes to rest (

v = 0

) and remains at rest for

t = 10

20

s. The correct graph shows a linear decrease from -100 m/s to -200 m/s over 10 s, then zero velocity thereafter.

JEE Main · 2022 · 27 Jul 2022 · Shift 1 · Single correct option

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