A direct current of 4 A and an alternating current of peak value 4 A flow through resistance of 3Ω and 2Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be :
(A)3:2
(B)3:1✓ Correct
(C)3:4
(D)4:3
Answer: (B)
Solution
Heat produced by DC: H1=i2R1t=(4)2×3×t=48t. For AC, the rms current is irms=i0/2=4/2, so heat produced is H2=irms2R2t=(16/2)×2×t=16t. The ratio H1:H2=48t:16t=3:1.
JEE Main · 2022 · 27 Jul 2022 · Shift 1 · Single correct option