$\mathrm{SO}_{2} \mathrm{Cl}_{2}$ on reaction with excess of water results into acidic mixture $\mathrm{SO}_{2} \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+2 \mathrm{HCl}$ 16 moles of NaOH is required for the complete neutralisation of the resultant acidic mixture. The number of moles of $\mathrm{SO}_{2} \mathrm{Cl}_{2}$ used is :

JEE Main · 2022 · 25 Jul 2022 · Shift 1 · Some Basic Concepts of Chemistry

SO_{2} Cl_{2}

on reaction with excess of water results into acidic mixture

SO_{2} Cl_{2} + 2 H_{2} O \to H_{2} SO_{4} + 2 HCl

16 moles of NaOH is required for the complete neutralisation of the resultant acidic mixture. The number of moles of

SO_{2} Cl_{2}

used is :

Answer: (C)

Let the number of moles of

SO_{2} Cl_{2}

x

. From the stoichiometry,

x

moles of

SO_{2} Cl_{2}

produces

x

moles of

H_{2} SO_{4}

and

2 x

moles of

HCl

. The total number of

H^{+}

ions =

2 x + 2 x = 4 x

. For complete neutralization,

n (H^{+}) = n (OH^{-})

, so

4 x = 16

, giving

x = 4

JEE Main · 2022 · 25 Jul 2022 · Shift 1 · Single correct option