In 1st case, Carnot engine operates between temperatures 300 K and 100 K . In 2nd case, as shown in the figure, a combination of two engines is used. The efficiency of this combination (in 2nd case) will be :
(A)same as the 1st case✓ Correct
(B)always greater than the 1st case
(C)always less than the 1st case
(D)may increase or decrease with respect to the 1st case
Answer: (A)
Solution
First case: η1=1−300100=32. Second case with two engines in series (300K→200K→100K): ηA=1−300200=31, ηB=1−200100=21. Combined efficiency: ηnet=ηA+ηB−ηAηB=31+21−61=32. Thus, both cases have the same efficiency.
JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Single correct option