The normality of $\mathrm{H}_{2} \mathrm{SO}_{4}$ in the solution obtained on mixing 100 mL of $0.1 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ with 50 mL of 0.1 M NaOH is $\_\_\_\_$ $\times 10^{-1} \mathrm{~N}$. (Nearest Integer)

JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Some Basic Concepts of Chemistry

The normality of

H_{2} SO_{4}

in the solution obtained on mixing 100 mL of

0.1 M H_{2} SO_{4}

with 50 mL of 0.1 M NaOH is

____

\times 1 0^{- 1} N

. (Nearest Integer)

Answer: 1

Calculate equivalents:

After neutralization:

Normality =

\frac{15}{150}

= 0.1 N = 1 × 10⁻¹ N

Therefore, x = 1

JEE Main · 2022 · 27 Jul 2022 · Shift 2 · Integer answer