In the structure of $\mathrm{SF}_{4}$, the lone pair of electrons on $S$ is in.

(A) equatorial position and there are two lone pair-bond pair repulsions at $90^{\circ}$

(B) equatorial position and there are three lone pair-bond pair repulsions at $90^{\circ}$

(C) axial position and there are three lone pair bond pair repulsion at $90^{\circ}$.

(D) axial position and there are two lone pair bond pair repulsion at $90^{\circ}$.

JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Chemical Bonding and Molecular Structure

In the structure of

SF_{4}

, the lone pair of electrons on

S

is in.

(A)equatorial position and there are two lone pair-bond pair repulsions at $9 0^{\circ}$ ✓ Correct
(B)equatorial position and there are three lone pair-bond pair repulsions at $9 0^{\circ}$
(C)axial position and there are three lone pair bond pair repulsion at $9 0^{\circ}$ .
(D)axial position and there are two lone pair bond pair repulsion at $9 0^{\circ}$ .

Answer: (A)

Solution

SF_{4}

has sp³d hybridization with a see-saw geometry. The sulfur atom has one lone pair and four bond pairs. To minimize repulsion, the lone pair occupies an equatorial position (where it experiences less repulsion). In this geometry, the lone pair has two 90° repulsions with the axial bond pairs. Therefore, the lone pair is in the equatorial position with two lone pair-bond pair repulsions at 90°.

Structure See-Saw structure — See-Saw structure

JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Single correct option

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JEE Main · 2022 · 28 Jun 2022 · Shift 2 · Chemical Bonding and Molecular Structure

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