A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of $15 \Omega$. The galvanometer (G) shows null deflection when tapping key is at 43 cm mark from end A. If the end correction for end A is 2 cm, then the determined value of $R$ will be ______ $\Omega$.

JEE Main · 2022 · 28 Jun 2022 · Shift 1 · Current Electricity

A meter bridge setup is shown in the figure. It is used to determine an unknown resistance R using a given resistor of

15Ω

. The galvanometer (G) shows null deflection when tapping key is at 43 cm mark from end A. If the end correction for end A is 2 cm, then the determined value of

R

will be ______

Ω

Answer: 19

Solution

Using the balanced Wheatstone bridge condition with end correction:

\frac{15}{43 + 2} = \frac{R}{102 - 45}

. Here, the effective length from A is

43 + 2 = 45

cm, and from the other end is

100 - 43 = 57

cm. So

\frac{15}{45} = \frac{R}{57}

, giving

R = \frac{15 \times 57}{45} = \frac{855}{45} = 19Ω

JEE Main · 2022 · 28 Jun 2022 · Shift 1 · Integer answer

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