The hybridization of P exhibited in $\ce{PF5}$ is $\mathrm{sp}^{x}\mathrm{d}^{y}$. The value of $y$ is ______.

JEE Main · 2022 · 28 Jun 2022 · Shift 1 · Chemical Bonding and Molecular Structure

The hybridization of P exhibited in

PF X_{5}

sp^{x} d^{y}

. The value of

y

is ______.

Answer: 1

Solution

PF X_{5}

, phosphorus forms 5 sigma bonds with 5 fluorine atoms and has no lone pairs. The steric number is 5, requiring 5 hybrid orbitals. This corresponds to

sp^{3} d

hybridization, where one s orbital, three p orbitals, and one d orbital are mixed.

Comparing with

sp^{x} d^{y}

x = 3

and

y = 1

.

Therefore,

y = 1

JEE Main · 2022 · 28 Jun 2022 · Shift 1 · Integer answer

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