JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Heat & Thermodynamics

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A vessel contains 16 g of hydrogen and 128 g of oxygen at standard temperature and pressure. The volume of the vessel in

cm^{3}

is :

(A) $72 \times 1 0^{5}$
(B) $32 \times 1 0^{5}$
(C) $27 \times 1 0^{4}$ ✓ Correct
(D) $54 \times 1 0^{4}$

Answer: (C)

Solution

Calculate the number of moles of each gas:

Moles of $H_{2}$ = $\frac{16}{2} = 8$ moles
Moles of $O_{2}$ = $\frac{128}{32} = 4$ moles
Total moles = 12 moles

At STP, 1 mole of gas occupies 22.4 L =

22.4 \times 1 0^{3}

cm³.

Volume =

12 \times 22.4 \times 1 0^{3} = 268.8 \times 1 0^{3} \approx 27 \times 1 0^{4}

cm³.

JEE Main · 2022 · 29 Jun 2022 · Shift 2 · Single correct option

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