Consider the ions/molecule $\mathrm{O}_{2}^{+}, \mathrm{O}_{2}, \mathrm{O}_{2}^{-}, \mathrm{O}_{2}^{2-}$ For increasing bond order the correct option is :

(A) $\mathrm{O}_{2}^{2-}<\mathrm{O}_{2}^{-}<\mathrm{O}_{2}<\mathrm{O}_{2}^{+}$

(B) $\mathrm{O}_{2}^{-}<\mathrm{O}_{2}^{2-}<\mathrm{O}_{2}<\mathrm{O}_{2}^{+}$

(C) $\mathrm{O}_{2}^{-}<\mathrm{O}_{2}^{2-}<\mathrm{O}_{2}^{+}<\mathrm{O}_{2}$

(D) $\mathrm{O}_{2}^{-}<\mathrm{O}_{2}^{+}<\mathrm{O}_{2}^{2-}<\mathrm{O}_{2}$

JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Chemical Bonding and Molecular Structure

Consider the ions/molecule

O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2 -}

For increasing bond order the correct option is :

Answer: (A)

Bond order = (electrons in BMO - electrons in ABMO)/2

For oxygen species (16 total electrons in O₂):

Increasing bond order:

O_{2}^{2 -} < O_{2}^{-} < O_{2} < O_{2}^{+}

JEE Main · 2022 · 26 Jun 2022 · Shift 1 · Single correct option