Two identical cells each of emf 1.5 V are connected in parallel across a parallel combination of two resistors each of resistance 20Ω. A voltmeter connected in the circuit measures 1.2 V . The internal resistance of each cell is
(A)2.5Ω
(B)4Ω
(C)5Ω✓ Correct
(D)10Ω
Answer: (C)
Solution
For two identical cells in parallel, the effective emf is 1.5 V and effective internal resistance is r/2. The external resistance is 20∥20=10Ω.
Using V=E−i(r/2): 1.2=1.5−i(r/2) i(r/2)=0.3
The current i=10+r/21.5, so: 10i+i(r/2)=1.5 10i=1.5−0.3=1.2 i=0.12A
Therefore r=0.120.6=5Ω
JEE Main · 2022 · 24 Jun 2022 · Shift 1 · Single correct option