What will be the most suitable combination of three resistors $A=2 \Omega$, $B=4 \Omega$, $C=6 \Omega$ so that $\left(\frac{22}{3}\right) \Omega$ is equivalent resistance of combination?

(B) Parallel combination of A and B connected in series with C.

(A) Parallel combination of A and C connected in series with B .

(C) Series combination of A and C connected in parallel with B.

(D) Series combination of B and C connected in parallel with A.

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Current Electricity

What will be the most suitable combination of three resistors

A = 2Ω

B = 4Ω

C = 6Ω

so that

(\frac{22}{3}) Ω

is equivalent resistance of combination?

Answer: (B)

For parallel combination of A and B:

R_{A B} = \frac{2 \times 4}{2 + 4} = \frac{4}{3} Ω

. Connected in series with C:

R_{e q} = \frac{4}{3} + 6 = \frac{4 + 18}{3} = \frac{22}{3} Ω

. This matches the required value.

JEE Main · 2022 · 24 Jun 2022 · Shift 2 · Single correct option