JEE Main · 2022 · 25 Jun 2022 · Shift 2 · Current Electricity

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If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be:

(A) $\frac{KS}{( S + G )}$
(B) $\frac{( G + S )}{nKS}$
(C) $\frac{n K S}{( G + S )}$
(D) $\frac{nK ( G + S )}{S}$ ✓ Correct

Answer: (D)

Solution

The figure of merit is

K = \frac{I _{g}}{θ}

, where

I_{g}

is the galvanometer current and

θ

is the deflection. For

n

deflections,

I_{g} = K n

. In a shunt configuration, the total current is

I = I_{g} \cdot \frac{G + S}{S}

. Substituting

I_{g} = K n

I = \frac{n K ( G + S )}{S}

JEE Main · 2022 · 25 Jun 2022 · Shift 2 · Single correct option

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