JEE Main · 2022 · 25 Jun 2022 · Shift 1 · Current Electricity

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A resistor develops 300 J of thermal energy in 15 s, when a current of 2 A is passed through it. If the current increases to 3 A, the energy developed in 10 s is ______ J.

Answer: 450

Solution

The heat developed in a resistor is given by

H = i^{2} R t

.

First, find the resistance using the initial conditions:

300 = 2^{2} \times R \times 15

R = \frac{300}{60} = 5 Ω

Now, for

i = 3

t = 10

s, and

R = 5 Ω

H = 3^{2} \times 5 \times 10 = 9 \times 50 = 450 J

JEE Main · 2022 · 25 Jun 2022 · Shift 1 · Integer answer

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