JEE Main · 2022 · 25 Jun 2022 · Shift 1 · Coordination Compounds

White precipitate of AgCl dissolves in aqueous ammonia solution due to formation of :

(A) $[Ag (NH_{3})_{4}] Cl_{2}$
(B) $[Ag (Cl)_{2} (NH_{3})_{2}]$
(C) $[Ag (NH_{3})_{2}] Cl$ ✓ Correct
(D) $[Ag (NH_{3}) Cl] Cl$

Answer: (C)

Solution

Silver chloride (AgCl) is sparingly soluble in water but dissolves in aqueous ammonia due to the formation of a soluble complex.

The reaction is:

AgCl (s) + 2 NH_{3} (a q) \to [Ag (NH_{3})_{2}]^{+} + Cl^{-}

The complex formed is diamminesilver(I) chloride,

[Ag (NH_{3})_{2}] Cl

, which is soluble in water.

Silver(I) typically forms linear complexes with coordination number 2, not 4, so option (A) is incorrect. The complex does not contain chloride as a ligand, eliminating options (B) and (D).

The answer is

[Ag (NH_{3})_{2}] Cl

JEE Main · 2022 · 25 Jun 2022 · Shift 1 · Single correct option

Practise more: all JEE Main PYQs on Coordination Compounds →

JEE Main · 2022 · 25 Jun 2022 · Shift 1 · Coordination Compounds

Solution

More JEE Main questions on Coordination Compounds