JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Gravitation

Consider two satellites

S_{1}

and

S_{2}

with periods of revolution 1 hr. and 8 hr. respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite

S_{1}

to the angular velocity of satellites

S_{2}

is:

(A) $1 : 8$
(B) $1 : 4$
(C) $2 : 1$
(D) $8 : 1$ ✓ Correct

Answer: (D)

Solution

Angular velocity

ω = \frac{2 π}{T}

, where

T

is the period of revolution.

For satellite

S_{1}

ω_{1} = \frac{2 π}{T _{1}} = \frac{2 π}{1}

For satellite

S_{2}

ω_{2} = \frac{2 π}{T _{2}} = \frac{2 π}{8}

Ratio:

\frac{ω _{1}}{ω _{2}} = \frac{2 π /1}{2 π /8} = \frac{8}{1} = 8 : 1

The answer is (D)

8 : 1

JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Single correct option

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